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 Post subject: Math ...Help ..Thank You
PostPosted: Nov 10, 2007 - 01:40 AM 
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~ Tuổi Thơ ~
~ Tuổi Thơ ~

Joined: Mar 22, 2005 - 08:13 AM
Posts: 115
#51 . Investment A man has $235,000 invested in three properties. One earns 12%, one 10%, and one 8%. His annual income from the properties is $22,500 and the amount invested at 8% is twice that invested at 12%. How much is invested in each property?

Answer $50,000 at 12%, $85,000 at 10%, and $100,000 at 8%

I am doing this practic problem in order to get ready for my exam. I tried to solve the problem in many difeerent ways but I couln't get the answer. Could anyone please help me to show work for this problẹm Thank you very much.

Oh currently i am learning about matrix, so this problem relate to matrix. thanx in advanced.


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PostPosted: Nov 10, 2007 - 02:00 AM 
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~ Mới Lớn ~
~ Mới Lớn ~

Joined: Jan 07, 2005 - 06:48 PM
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let
x = amounted invested at 12%
y= amounted invested at 10%
z= amounted invested at 8%
x+y+z = 235,000
since amount at 8% is twice of amount at 12%. z=2x
x+y+z=x+y+2x
3x + y = 235,000
Also, 3(.08)x + (.1)y = 22,500

use Cramer's ruleto find x and y.
z = 235,000-x-y

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PostPosted: Nov 10, 2007 - 09:57 PM 
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ĸïиġ Jaмeš

Joined: Sep 02, 2006 - 06:16 AM
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gimme a sec

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PostPosted: Nov 10, 2007 - 11:05 PM 
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ĸïиġ Jaмeš

Joined: Sep 02, 2006 - 06:16 AM
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here you go bengoc :D

http://www.hotlinkfiles.com/files/59428 ... stment.doc

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PostPosted: Nov 10, 2007 - 11:14 PM 
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~ Tuổi Thơ ~
~ Tuổi Thơ ~

Joined: Mar 22, 2005 - 08:13 AM
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thx


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PostPosted: Jan 24, 2018 - 11:23 PM 
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~ Tuổi Thơ ~
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PostPosted: Feb 12, 2018 - 01:45 AM 
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